如题：设计一个M*N的二维数组类，要求重载+、-运算符。
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
| #include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
const int M = 2;
const int N = 3;
class Array{
public:
Array(){}
Array(int n[M][N]){
for (int i = 0;i < M;i ++)
memcpy(arr[i],n[i],sizeof(n[N]));
}
void show(){
for (int i = 0;i < M;i++){
for (int j = 0;j < N;j++){
cout << '\t' << arr[i][j];
}
puts("");
}
}
void set(){
cout << "请输入2*3的整型数组：\n";
for (int i = 0;i < M;i++)
for (int j = 0;j < N;j++) cin >> arr[i][j];
}
Array operator+ (Array& a){
Array temp;
for (int i = 0;i < M;i++){
for (int j = 0;j < N;j++){
temp.arr[i][j] = this->arr[i][j]+a.arr[i][j];
}
}
return temp;
}
Array operator- (Array& a){
Array temp;
for (int i = 0;i < M;i++){
for (int j = 0;j < N;j++){
temp.arr[i][j] = this->arr[i][j]-a.arr[i][j];
}
}
return temp;
}
private:
int arr[M][N];
};
int main(){
int a[M][N] = {1,2,3,4,5,6};
Array A(a),B,C,D;
B.set();
cout << "Array A:" << endl;
A.show();
cout << "Array B:" << endl;
B.show();
C = A + B;
cout << "Array C=A+B:" << endl;
C.show();
D = A - B;
cout << "Array D=A-B:" << endl;
D.show();
return 0;
}
|
